(1+9/7)x^2-2(5+9/7)x+16+9/7=0

Solution for (1+9/7)x^2-2(5+9/7)x+16+9/7=0 equation:

(1+9/7)x^2-2(5+9/7)x+16+9/7=0


Domain of the equation: 7)x^2!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 7)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(9/7+1)x^2-2(9/7+5)x+16+9/7=0

We multiply parentheses

-18x^2+(9/7+1)x^2-10x+16+9/7=0

We calculate fractions


-18x^2-10x+16=0

a = -18; b = -10; c = +16;
Δ = b2-4ac
Δ = -102-4·(-18)·16
Δ = 1252
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1252}=\sqrt{4*313}=\sqrt{4}*\sqrt{313}=2\sqrt{313}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{313}}{2*-18}=\frac{10-2\sqrt{313}}{-36}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{313}}{2*-18}=\frac{10+2\sqrt{313}}{-36}
$